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x^2+3x=-8x+14
We move all terms to the left:
x^2+3x-(-8x+14)=0
We get rid of parentheses
x^2+3x+8x-14=0
We add all the numbers together, and all the variables
x^2+11x-14=0
a = 1; b = 11; c = -14;
Δ = b2-4ac
Δ = 112-4·1·(-14)
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{177}}{2*1}=\frac{-11-\sqrt{177}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{177}}{2*1}=\frac{-11+\sqrt{177}}{2} $
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